交换机连接路由器的那个端口也是一个冲突域啊.

唉,我真是笨啊

QUESTION NO: 21
The corporate LAN shown in the TestKing network uses IP network 172.28.4.0/22 for all departments. All workstations use 172.28.4.1 as a default gateway address.Network administrators have recently become concerned that excessive broadcasts are slowing network performance. Which change is most likely to reduce broadcast traffic on the corporate LAN?

TK公司的局域网使用的都是172.28.4.0/22网段,所有主机的缺省网关地址为172.28.4.1
最近网管发现过多的广播数据包正在降低网络的性能,那么应该采用那个方法来减少广播的冲突?



A. Configure an access control list on the router to prevent broadcast forwarding.
B. Configure each NIC and switch port to operate at full duplex.
C. Change the router-to-switch connection from Fast Ethernet to Gigabit Ethernet.
D. Implement VLANs after creating IP subnets for each department.
E. Increase the number of switches in the network closet of each department.

解析:如果想隔离广播域,只能利用三层设备或者划分VLAN,本题中,只有选项D才能实现这一点.

答案

QUESTION NO: 22 DRAG DROP

左边是一些Cisco连接线缆,右边是三种需要连接的情况,选择正确的线缆



解析:Cisco的RJ45有三种线
straight-throught 直通线 连接不同种类设备
crossvoer 交叉线 两端标准不同 连接相同种类设备
rollvoer 翻转线 两端线序完全相反 用来调适网络设备

答案:

支持，有些题正好我也在看

QUESTION NO: 23
Two buildings on the San Jose campus of the TestKing network must be connected to use Ethernet with a bandwidth of at least 100 Mbps. The company is concerned about possible problems from voltage differences between the two buildings. Which media type should be used for the connection?

]

两个建筑物必须使用带宽为100 Mbps的以太连接，公司正在考虑各种解决方案以解决两个建筑物之间的电压不同的问题.请选择连接使用的介质类型?

A. STP cable
B. Coaxial cable
C. Fiber optic cable
D. UTP cable
E. None of the above

解析：既然电压不稳，必然会对线路上的数据通信发生影响，为了解决这个问题，应该选择不使用电信号的传输介质：光纤就好

答案：C

这也能行啊，，什么时候我也学学样子

引用:

原帖由 Angelgogo 于 2007-5-17 10:20 发表
这也能行啊，，什么时候我也学学样子

好呀，建议你来翻译NP的题库.

不错，挺好的。谢谢分享！
还没有细看，改天细看，发现问题再向你来请教！

第二部分 根据要求设计IP地址(68题)

QUESTION NO: 1
You have the binary number 10011101. Convert it to its decimal and hexadecimal equivalents. (Select two answer choices)
二进制数为10011101，转化为十进制和十六进制结果为:

A. 158
B. 0x9D
C. 156
D. 157
E. 0x19
F. 0x9F

解析：本题考察数制基础知识
二进制->十进制 按权展开法 10011101 = 128+0+0+16+8+4+0+1 = 157
二进制->十六进制 每4位作变化 1001 = 9 1101 = 13(D)

答案：B，D

晕,都过了快一年了,怎么还是这几题....

QUESTION NO: 2
The subnet mask on the serial interface of a router is expressed in binary as 11111000 for the last octet. How do you express

the binary number 11111000 in decimal?
路由器串行口的子网掩码，最后一组为11111000，用十进制表示应该是

A. 210
B. 224
C. 240
D. 248
E. 252

解析：按权展开法:128 + 64+32+16+8 = 248.

答案：D

ding 这个很有用~~~

QUESTION NO: 3
Which one of the binary number ranges shown below corresponds to the value of the first
octet in Class B address range?
下列哪个二进制数是B类网址的开始8位的地址范围?

A. 10000000-11101111
B. 11000000-11101111
C. 10000000-10111111
D. 10000000-11111111
E. 11000000-10111111

解析：B类地址范围是128.0.0.0 到 191.255.255.255.将头一位十进制转化为二进制便可

答案：C

QUESTION NO: 4

How would the number 231 be expressed as a binary number?
231转化为二进制应该是?

A. 11011011
B. 11110011
C. 11100111
D. 11111001
E. 11010011

解析：除2取余法，减权定位法都可以计算出来

答案：C

QUESTION NO: 5
How would the number 172 be expressed in binary form?
172用二进制表示应该是？

A. 10010010
B. 10011001
C. 10101100
D. 10101110

解析同上

答案：C

QUESTION NO: 6
The MAC address for your PC NIC is: C9-3F-32-B4-DC-19. What is the address of
the OUI portion of this NIC card, expressed as a binary number?
你的电脑网卡的MAC地址为C9-3F-32-B4-DC-19，哪一部分是OUI地址，表示为二进制应该是？

A. 11001100-00111111-00011000
B. 11000110-11000000-00011111
C. 11001110-00011111-01100000
D. 11001001-00111111-00110010
E. 11001100-01111000-00011000
F. 11111000-01100111-00011001

解析：IEEE规定了每一个厂商的“组织唯一识别码”organizationally unique identifier(OUI)，该厂商出品的网卡的MAC地址前一半地址就

是这个OUI本例中即为：C9-3F-32
先变成十进制
C9 = (12x16) + 9 = 201
3F = (3x16) + 15 = 63
32 = (3x16) + 2 = 50
再变成二进制
201 = 11001001
63 = 00111111
50 = 00110010

Answer: D

这个是要多学学呢，为了考证多关注一下吧``

QUESTION NO: 7
How do you express the binary number 10110011 in decimal form?
将二进制数10110011表示为十进制应该为

A. 91
B. 155
C. 179
D. 180
E. 201
F. 227

解析:按权展开法是基本的二进制转十进制的算法,必须牢固掌握.
1 0 1 1 0 0 1 1
128 64 32 16 8 4 2 1
128 + 0 + 32 +16 + 0 + 0 +2 +1 = 179

Answer: C

QUESTION NO: 8 DRAG DROP
Convert the hex and decimal numbers on the left into binary, and match them to
their corresponding slot on the right. (Not all of the hexadecimal and decimal
numbers will be used)



将左边的十进制数和十六进制数转化成二进制，然后和右边的值匹配

解析：
170 (Decimal) = 10101010
192 (Decimal) = 11000000
F1 (241 = Decimal) = 11110001
9F (159 = Decimal) = 10011111

答案：