QUESTION NO: 48
What is the network address for a host with the IP address 201.100.5.68/28?
某主机的地址为201.100.5.68/28,它的网段地址是什么?

A. 201.100.5.0
B. 201.100.5.32
C. 201.100.5.64
D. 201.100.5.65
E. 201.100.5.31
F. 201.100.5.1

解析:掩码是/28 255.255.255.240
256-240=16,子网应该是16的倍数
201.100.5.0
201.100.5.16
201.100.5.32
.....
201.100.5.240
题中要求的网段号,可见201.100.5.68在C. 201.100.5.64子网内

Answer: C

QUESTION NO: 49
Which of the following IP addresses fall into the CIDR block of 115.54.4.0/22? Select three
下列哪些IP地址在CIDR块地址115.54.4.0/22范围里面？(三选)

A. 115.54.8.32
B. 115.54.7.64
C. 115.54.6.255
D. 115.54.3.32
E. 115.54.5.128
F. 115.54.12.128

解析：本题考察CIDR知识，既然说明了是个CIDR地址块，我们就不要再题这是个A类地址啦。
IP是115.54.4.0 掩码是255.255.252.0
说明这是个被人划过的子网，范围是115.54.4.0 ~115.54.7.255

Answer: B, C, E

QUESTION NO: 50
If an Ethernet port on router was assigned an IP address of 172.16.112.1/20, what is
the maximum number of hosts allowed on this subnet?
如果路由器的某个以太端口被配置了IP地址172.16.112.1/20，那么该端口所连接的子网，最大主机数目是多少？

A. 1024
B. 2046
C. 4094
D. 4096
E. 8190

解析：看来留给主机位有12比特，那么2的12次方＝4096
4096-2=4094

Answer: C
其实这个端口也占了1个。。

QUESTION NO: 51
You work as network consultant. Your customer, TestKing Inc, has a class C
network license. TestKing wants you to subnet the network to provide a separate
subnet for each of its 5 departments. Each subnet must support at least 24 hosts.
Which network mask should you use?
你的客户TK公司拥有一个C类网段，TK公司想让你为其划分子网来为5个部门分别提供一个独立的子网，每一个子网必须支持24台主机以上
你应该使用那个子网掩码呢？

A. 255.255.255.192
B. 255.255.255.224
C. 255.255.255.240
D. 255.255.255.248
E. 255.255.255.252
F. 255.255.255.254

解析：24台主机，主机位留5位 5个子网 子网位留3位

答案：B

版主努力的狠，大家支持一下。

QUESTION NO: 52
Your TestKing trainee Bob asks you what 11111001 binary is in decimal. What
should you tell him?
老板问题二进制的11111001变成十进制是啥？你怎么回答？

A. 6
B. 193
C. 225
D. 241
E. 249

解析：还有这样喜欢研究技术的老板！
11111001 按权展开 128+64+32+16+8+1 = 249

答案：E

QUESTION NO: 53
What is the maximum number of IP addresses that can be assigned to hosts on a
local subnet that use the 255.255.255.224 subnet mask?
使用掩码255.255.255.224的本地子网，可以分配给主机的最大数目地址是多少？

A. 14
B. 15
C. 16
D. 30
E. 31
F. 32

解析：224是11100000，留给主机位5位，2的5次方－2＝30

答案：D

QUESTION NO: 54
Which of the following IP addresses for the network 27.35.16.32/28 can be assigned
to hosts? (Choose three)
下列哪些地址可以分配给网络27.35.16.32/28的主机？(3个)

A. 27.35.16.32
B. 27.35.16.33
C. 27.35.16.48
D. 27.35.16.47
E. 27.35.16.45
F. 27.35.16.44

解析：其实就是分析这个网段的地址范围.
27.35.16.32子网掩码是255.255.255.240
256-240=16 那么最后一个八位组必然是16的倍数
主机地址是:16的倍数+1 ～16的下一个倍数－2

答案：B,E,F

QUESTION NO: 55 DRAG DROP
TestKing has three locations and has plans to redesign the network accordingly. The
networking team received 192.168.236.0 to use as the addressing for entire network
from the administrator. After subnetting the address, the team is ready to assign the
address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing
protocol. As a member of the networking team, you must address the network and
at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router
interface. One of the routers is partially configured. Move the mouse over a router
to view its configuration (** This information is missing**). Not all of the host
addresses on the left will be used.



拖拽题：
TK公司有三个分部，准备重新设置网络划分子网，管理员给网络分配的地址是192.168.236.0
管理员计划配置启动全0子网和RIPv2作为路由协议，作为网络管理团队的一员，你必须分配地址的同时必须保留一些地址给将来备用
图中看到：一个路由器做了一些配置，将合适的主机地址放入正确的位置(不是所有地址都用上)

解析：RIPv2支持VLSM，可以使用不同的掩码，思路同42题
3个路由器连接3个子网，需要的主机数目分别是：11,76,43
2的4次方-2=14 可见/28适合
2的7次方－2＝126 可见/25适合
2的6次方－2＝62 可见/26适合
两个路由器之间串行链路用/30正好

答案：看图

QUESTION NO: 56 DRAG DROP
TestKing has three locations and has plans to redesign the network accordingly. The
networking team received 192.168.132.0 to use as the addressing for entire network
from the administrator. After subnetting the address, the team is ready to assign the
address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing
protocol. As a member of the networking team, you must address the network and
at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router
interface. One of the routers is partially configured. Move the mouse over a router
to view its configuration (** This information is missing**). Not all of the host
addresses on the left will be used.



TK公司有三个分部，准备重新设置网络划分子网，管理员给网络分配的地址是192.168.236.0
管理员计划配置启动全0子网和RIPv2作为路由协议，作为网络管理团队的一员，你必须分配地址的同时必须保留一些地址给将来备用
图中看到：一个路由器做了一些配置，将合适的主机地址放入正确的位置(不是所有地址都用上)

解析：RIPv2支持VLSM，可以使用不同的掩码，
3个路由器连接3个子网，需要的主机数目分别是：88,59,19
2的5次方-2=32 可见/27适合19
2的7次方－2＝126 可见/25适合88
2的6次方－2＝62 可见/26适合59
两个路由器之间串行链路用/30
虽然用了子接口,但思路相同

答案：见图

QUESTION NO: 57
In network that support VLSM, which network mask should be used for
point-to-point WAN links in order to reduce waste of IP addresses?
在支持VLSM的网络中，为了减少地址浪费，应该在点对点的广域网链路上使用那个子网掩码？

A. /24
B. /30
C. /27
D. /26
E. /32

解析：串行掩码/30，一定要记住噢。

QUESTION NO: 58
The network 172.25.0.0 has been divided into eight equal subnets. Which of the
following IP addresses can be assigned to hosts in the third subnet if the ip
subnet-zero command is configured on the router? (Choose three)

网络172.25.0.0已经被分成了8个相等的子网，在启动了subnet zero的情况下，下列哪个IP地址属于第3个子网？(3个)

A. 172.25.78.243
B. 172.25.98.16
C. 172.25.72.0
D. 172.25.94.255
E. 172.25.96.17
F. 172.25.100.16

解析：本题关键在于找到这8个子网
subnet zero启用，全0子网和全1子网空用
2的3次方＝8
掩码应该是255.255.224.0 256-224=32 子网应该是
172.25.0.0
172.25.32.0
172.25.64.0
.....
172.25.224.0
第三个子网的IP范围是172.16.64.1～172.16.95.255

Answer: A, C, D

这是以前版本上的题吧?我觉得我见过呀.4月份发的,现在有新的吗?如果有请版主给我发一份吧,谢谢了!
firephoenix_love@126.com
我想在暑假考CCNA的...................................

这个是TestKing 640-801 V108的题目，我一天翻译一道题。
1000多道，还没有到十分之一。

we为什么我总是看不到拓扑的图呀
真是郁闷哦
还是感谢赵高同志

UESTION NO: 59 DRAG DROP
TestKing has three locations and has plans to redesign the network accordingly. The
networking team received 192.168.199.0 to use as the addressing for entire network
from the administrator. After subnetting the address, the team is ready to assign the
address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing
protocol. As a member of the networking team, you must address the network and
at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router
interface. One of the routers is partially configured. Move the mouse over a router
to view its configuration (** This information is missing**). Not all of the host
addresses on the left will be used.

TK公司有三个分部，准备重新设置网络划分子网，管理员给网络分配的地址是192.168.199.0
管理员计划配置启动全0子网和RIPv2作为路由协议，作为网络管理团队的一员，你必须分配地址的同时必
须保留一些地址给将来备用
图中看到：一个路由器做了一些配置，将合适的主机地址放入正确的位置(不是所有地址都用上)


解析：RIPv2支持VLSM，可以使用不同的掩码，
3个路由器连接3个子网，需要的主机数目分别是：3,43,110
2的3次方-2=6 可见/29适合3
2的7次方－2＝126 可见/25适合110
2的6次方－2＝62 可见/26适合43
两个路由器之间串行链路用/30
虽然用了子接口,但思路相同

答案：见图

QUESTION NO: 60 DRAG DROP
TestKing has three locations and has plans to redesign the network accordingly. The
networking team received 192.168.197.0 to use as the addressing for entire network
from the administrator. After subnetting the address, the team is ready to assign the
address.
The administrator plans to configure ip subnet-zero and use RIP v2 as the routing
protocol. As a member of the networking team, you must address the network and
at the same time converse unused addresses for future growth.
Being mindful of these goals, drag the host addresses on the left to the correct router
interface. One of the routers is partially configured. Move the mouse over a router
to view its configuration (** This information is missing**). Not all of the host
addresses on the left will be used.



TK公司有三个分部，准备重新设置网络划分子网，管理员给网络分配的地址是192.168.197.0
管理员计划配置启动全0子网和RIPv2作为路由协议，作为网络管理团队的一员，你必须分配地址的同时必
须保留一些地址给将来备用
图中看到：一个路由器做了一些配置，将合适的主机地址放入正确的位置(不是所有地址都用上)
解析：RIPv2支持VLSM，可以使用不同的掩码，思路相同。
答案：见图


70

我们学习NA的人大有帮助啦
还望楼主继续发贴

[ 本帖最后由 何时才能飞 于 2007-7-10 20:58 编辑 ]

赵老师在吗？
你看一下第三道问题的答案是不是写错了.有可能是理解有误,因为我的english和电脑基础知识都很差.

引用:

原帖由 何时才能飞 于 2007-7-10 21:04 发表
赵老师在吗？
你看一下第三道问题的答案是不是写错了.有可能是理解有误,因为我的english和电脑基础知识都很差.

广播域不用说了，路由器分成了2个

右边的交换机，连接了6个设备(5个电脑，1个路由器) 自然是6个冲突域，加上左边的1个，7个。

欢迎大家参与探讨。